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Complex Trigonometric Functions

Definition

Let z∈Cz\in\mathbb{C}. The complex sine function sin⁡z\sin z and the complex cosine function cos⁡z\cos z are defined as

sin⁡z=∑n=0∞(−1)nz2n+1(2n+1)!=z−z33!+z55!−⋯ ,cos⁡z=∑n=0∞(−1)nz2n(2n)!=1−z22!+z44!−⋯ ,\begin{aligned} \sin z&=\sum_{n=0}^{\infty} \frac{(-1)^{n} z^{2 n+1}}{(2 n+1) !}\\ &=z-\frac{z^3}{3!}+\frac{z^5}{5!}-\cdots,\\ \cos z&=\sum_{n=0}^{\infty} \frac{(-1)^{n} z^{2 n}}{(2 n) !}\\ &=1-\frac{z^2}{2!}+\frac{z^4}{4!}-\cdots, \end{aligned}

where the powers znz^n are defined by repeated complex multiplication and can be evaluated in polar form by De Moivre's formula.


Interpretation

The complex sine and cosine extend the real trigonometric functions to complex inputs. A complex number has no point on the unit circle to read the values from, so the definition uses infinite series instead: each power znz^n is computed by complex multiplication, and the terms are added up.

The sine series contains only odd powers and the cosine series only even powers, with alternating signs and factorials in the denominators. Both series converge for every z∈Cz\in\mathbb{C}. For a real input xx the two sums are the familiar sin⁡x\sin x and cos⁡x\cos x, so nothing changes on the real axis: the definitions extend sine and cosine rather than replace them.

Off the real axis they behave differently, and the bound ∣sin⁡x∣≤1|\sin x|\le1 from the unit circle is lost. On the imaginary axis, (iy)2n=(−1)ny2n(\mathrm{i}y)^{2n}=(-1)^ny^{2n} cancels the alternating signs, so cos⁡(iy)=1+y22!+y44!+⋯\cos(\mathrm{i}y)=1+\frac{y^2}{2!}+\frac{y^4}{4!}+\cdots for real yy. This is larger than 11 for every y≠0y\neq0 and grows without bound; the Examples show the same for sin⁡i\sin\mathrm{i}.

A common slip concerns Euler's formula. The identity eiz=cos⁡z+isin⁡z\mathrm{e}^{\mathrm{i}z}=\cos z+\mathrm{i}\sin z holds for every complex zz, but for non-real zz the numbers cos⁡z\cos z and sin⁡z\sin z are in general not real, so they are not the real and imaginary parts of eiz\mathrm{e}^{\mathrm{i}z}. For z=iz=\mathrm{i}, ei⋅i=e−1\mathrm{e}^{\mathrm{i}\cdot\mathrm{i}}=\mathrm{e}^{-1} is real, while sin⁡i≈1.1752 i≠0\sin\mathrm{i}\approx1.1752\,\mathrm{i}\neq0.

Why the real sine and cosine are given by exactly these series is explained later by Taylor series.


Key Results

  • The complex sine and cosine functions remain periodic with period 2π2\pi.
  • The algebraic identities of real trigonometry, such as sin⁡2z+cos⁡2z=1\sin^2z+\cos^2z=1 and the addition formulas, continue to hold for complex arguments.
  • By Euler's formula, cos⁡z=eiz+e−iz2\cos z=\dfrac{\mathrm{e}^{\mathrm{i}z}+\mathrm{e}^{-\mathrm{i}z}}{2} and sin⁡z=eiz−e−iz2i\sin z=\dfrac{\mathrm{e}^{\mathrm{i}z}-\mathrm{e}^{-\mathrm{i}z}}{2\mathrm{i}}.
  • Unlike the real functions, sin⁡z\sin z and cos⁡z\cos z are unbounded on C\mathbb{C}: ∣sin⁡z∣|\sin z| can be larger than 11.

Examples

Since i3=−i\mathrm{i}^3=-\mathrm{i} and i5=i\mathrm{i}^5=\mathrm{i}, the signs in the series for sin⁡i\sin\mathrm{i} all turn positive:

sin⁡i=i+i3!+i5!+⋯=i(1+13!+15!+⋯ )=i e−e−12≈1.1752 i.\begin{aligned} \sin\mathrm{i}&=\mathrm{i}+\frac{\mathrm{i}}{3!}+\frac{\mathrm{i}}{5!}+\cdots\\ &=\mathrm{i}\left(1+\frac{1}{3!}+\frac{1}{5!}+\cdots\right)\\ &=\mathrm{i}\,\frac{\mathrm{e}-\mathrm{e}^{-1}}{2}\approx1.1752\,\mathrm{i}. \end{aligned}

So ∣sin⁡i∣≈1.1752>1|\sin\mathrm{i}|\approx1.1752>1, which no real sine value can reach. The same value follows from Euler's form: sin⁡i=e−1−e2i=i e−e−12\sin\mathrm{i}=\dfrac{\mathrm{e}^{-1}-\mathrm{e}}{2\mathrm{i}}=\mathrm{i}\,\dfrac{\mathrm{e}-\mathrm{e}^{-1}}{2}.


Prerequisites

Sources

Symbols: complex numbers, element of, infinity, pi, sum

Last updated: 20 October 2026 03:02