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Euler's Identity

Corollary

Setting z=πz=\pi in Euler's formula gives eiπ+1=0.\mathrm{e}^{\mathrm{i}\pi}+1=0.


Interpretation

Euler's identity is Euler's formula at the angle π\pi. For a real angle θ\theta, eiθ=cos⁡θ+isin⁡θ\mathrm{e}^{\mathrm{i}\theta}=\cos\theta+\mathrm{i}\sin\theta is the point on the unit circle at angle θ\theta, and θ=π\theta=\pi is half a turn.

The unit circle in the complex plane with an arc of angle pi from the point 1 to the point -1, which is e to the i pi.

The red arc runs anticlockwise from 1=ei01=\mathrm{e}^{\mathrm{i}0} through i=eiπ/2\mathrm{i}=\mathrm{e}^{\mathrm{i}\pi/2} and ends at −1-1: since cos⁡π=−1\cos\pi=-1 and sin⁡π=0\sin\pi=0, the imaginary part vanishes and eiπ=−1\mathrm{e}^{\mathrm{i}\pi}=-1. Adding 11 to both sides gives eiπ+1=0\mathrm{e}^{\mathrm{i}\pi}+1=0.

Read as multiplication, the identity says that multiplying by eiπ=−1\mathrm{e}^{\mathrm{i}\pi}=-1 is a half-turn about 00, that is, negation; two half-turns give e2πi=1\mathrm{e}^{2\pi\mathrm{i}}=1. The identity is famous for joining the constants 00, 11, π\pi, e\mathrm{e} and i\mathrm{i} in one short equation, but mathematically it is just a special case of Euler's formula.


Key Results


Examples

  • Substitute θ=π\theta=\pi into Euler's formula: eiπ=cos⁡π+isin⁡π=−1+i⋅0=−1\mathrm{e}^{\mathrm{i}\pi}=\cos\pi+\mathrm{i}\sin\pi=-1+\mathrm{i}\cdot0=-1. Adding 11 gives 00. Thus multiplication by eiπ\mathrm{e}^{\mathrm{i}\pi} sends z=2+3iz=2+3\mathrm{i} to (−1)(2+3i)=−2−3i(-1)(2+3\mathrm{i})=-2-3\mathrm{i}, a half-turn about the origin.

Prerequisites

Sources

Keywords: most beautiful formula Symbols: pi, theta

Last updated: 20 October 2026 03:02