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Radius and Interval of Convergence

Definition

For a given power series ∑n=0∞cn(x−a)n,\displaystyle \sum_{n=0}^\infty c_n (x-a)^n\text{,} its radius of convergence RR is a nonnegative real number or +∞+\infty such that the series converges if ∣x−a∣<R|x-a|<R and diverges if ∣x−a∣>R.|x-a|>R\text{.} The interval of convergence is the set of all values of xx for which the series converges.


Interpretation

The radius of convergence tells how far from the centre aa a power series converges. Apart from the boundary, only the distance ∣x−a∣|x-a| matters: the series converges at every xx within distance RR of the centre and diverges at every xx further away.

A number line centred at a with the interval from a minus R to a plus R marked as the region of convergence, the radius R shown as an arrow, divergence outside and the endpoints to be tested separately.

The figure shows the open interval (a−R,a+R)(a-R,a+R) where the series converges (absolutely), the radius RR as an arrow from the centre, and divergence outside. The endpoints a±Ra\pm R are drawn as open circles because the radius says nothing about them. The interval of convergence is (a−R,a+R)(a-R,a+R) together with those endpoints at which the series converges. For a=0a=0 and R=1R=1 all four cases occur: ∑nxn\displaystyle \sum_n x^n converges on (−1,1)(-1,1), ∑n≥1xn/n\displaystyle \sum_{n\ge1}x^n/n on [−1,1)[-1,1), ∑n≥1(−x)n/n\displaystyle \sum_{n\ge1}(-x)^n/n on (−1,1](-1,1], and ∑n≥1xn/n2\displaystyle \sum_{n\ge1}x^n/n^2 on [−1,1][-1,1].

Each series converges for ∣x−a∣<R|x-a|<R and diverges for ∣x−a∣>R|x-a|>R; what happens at the endpoints differs from series to series.

Every power series has such an R∈[0,+∞]R\in[0,+\infty]. The extreme cases are R=0R=0, where the series converges only at its centre, and R=+∞R=+\infty, where it converges for every real xx. In practice RR is computed with the ratio test, R=lim⁡n→∞∣cn/cn+1∣R=\lim_{n\to\infty}|c_n/c_{n+1}| when this limit exists, or with the root test, R=1/lim sup⁡∣cn∣1/nR=1/\limsup|c_n|^{1/n}, which always applies.

Inside the radius, the series converges uniformly on every closed interval [a−r,a+r][a-r,a+r] with r<Rr<R, and its sum can be differentiated term by term, as shown in convergence of power series.

Two slips are common. The interval is centred at aa, not at 00: for ∑nn(−2)n(x−3)n\displaystyle \sum_n n(-2)^n(x-3)^n in the Examples, R=12R=\tfrac{1}{2} and the interval is (52,72)(\tfrac{5}{2},\tfrac{7}{2}). And the endpoints must be tested separately, with tests for numerical series; their behaviour cannot be read from RR.


Key Results

  • The convergence of ∑n=0∞cn(x−a)n\displaystyle \sum_{n=0}^\infty c_n (x-a)^n at x=a−Rx=a-R and x=a+Rx=a+R is to be determined case-by-case.

Examples

  • The series ∑n=0∞n(−2)n(x−3)n\displaystyle \sum_{n=0}^\infty n(-2)^n (x-3)^n with R=1/2R = 1/2 centred at a=3a = 3, converges pointwise on (5/2,7/2)\left(5/2, 7/2\right) and uniformly on any closed interval within it. Its convergence interval is (5/2,7/2)\left(5/2, 7/2\right) since the series diverges at both endpoints.
  • The series ∑n=0∞2n2(x+2)n\displaystyle \sum_{n=0}^\infty 2^{n^2} (x+2)^n with R=0R = 0 centred at a=−2a = -2, converges solely at its centre x=−2.x = -2.

Prerequisites

Sources

Aliases: radius of convergence, interval of convergence, convergence radius Symbols: element of, infinity, sum

Last updated: 20 October 2026 03:02