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pp-norm and pp-metric

Definition

Let x=(x1,x2,…,xn)∈Rn\boldsymbol{x}=(x_1,x_2, \ldots,x_n)\in\mathbb{R}^n. For p∈[1,+∞)p\in[1,+\infty), the pp-norm, denoted ∥⋅∥p\|\cdot\|_p, is defined on Rn\mathbb{R}^n by:

∥x∥p=(∑i=1n∣xi∣p)1p.\|\boldsymbol{x}\|_p = \left(\sum_{i=1}^n |x_i|^p\right)^{\frac{1}{p}}.

For p=+∞p=+\infty one sets ∥x∥∞=max⁡1≤i≤n∣xi∣\|\boldsymbol{x}\|_\infty=\max\limits_{1\le i\le n}|x_i|, which is the limit of ∥x∥p\|\boldsymbol{x}\|_p as p→+∞p\to+\infty.

Correspondingly, the pp-metric dpd_p is defined as dp(x,y)=∥x−y∥pd_p(\boldsymbol{x},\boldsymbol{y})=\|\boldsymbol{x}-\boldsymbol{y}\|_p, that is,

dp(x,y)=(∑i=1n∣xi−yi∣p)1p(1≤p<+∞),d∞(x,y)=max⁡1≤i≤n∣xi−yi∣.\begin{aligned} d_p(\boldsymbol{x},\boldsymbol{y})&=\left(\sum_{i=1}^n |x_i-y_i|^p\right)^{\frac{1}{p}}\qquad (1\le p<+\infty),\\ d_\infty(\boldsymbol{x},\boldsymbol{y})&=\max_{1\le i\le n}|x_i-y_i|. \end{aligned}

The formula uses Exponentiation and Power twice: raise the coordinate magnitudes to pp, then take the 1/p1/p power of their sum. The value +∞+\infty is an Extended Real Number indexing the separate maximum-norm limit, not a finite exponent to substitute directly. Setting p=2p=2 recovers the Euclidean Norm.


Interpretation

The pp-norm is a way of measuring the size of a vector by raising each coordinate's absolute value to the pp-th power, summing them, and taking the pp-th root. The exponent decides how much weight the large coordinates get: p=1p=1 adds all coordinates equally, p=2p=2 gives the Euclidean length, and as p→+∞p\to+\infty only the largest coordinate counts.

Unit balls of the p-norm in the plane for p = 1, a diamond, p = 2, a circle, p = 4, a rounded square, and p = infinity, a square, nested inside one another.

The figure compares the unit balls {x ⁣:∥x∥p≤1}\{\boldsymbol{x}\colon\|\boldsymbol{x}\|_p\le1\} for p=1,2,4,∞p=1,2,4,\infty. As pp increases, these balls expand from the diamond towards the square, because ∥x∥q≤∥x∥p\|\boldsymbol{x}\|_q\le\|\boldsymbol{x}\|_p whenever p≤qp\le q. All four boundaries pass through (±1,0)(\pm1,0) and (0,±1)(0,\pm1): a vector with a single nonzero coordinate has the same pp-norm for every pp.

The restriction p≥1p\ge1 is needed for the triangle inequality. For p=12p=\tfrac{1}{2} the formula gives ∥(1,0)∥1/2=∥(0,1)∥1/2=1\|(1,0)\|_{1/2}=\|(0,1)\|_{1/2}=1 but ∥(1,1)∥1/2=(1+1)2=4>1+1\|(1,1)\|_{1/2}=(1+1)^2=4>1+1. Geometrically, the set {x ⁣:∥x∥1/2≤1}\{\boldsymbol{x}\colon\|\boldsymbol{x}\|_{1/2}\le1\} is pinched inwards between the axes: it contains (1,0)(1,0) and (0,1)(0,1), but not the midpoint (12,12)(\tfrac{1}{2},\tfrac{1}{2}), whose value is 22.

Different pp give different distances but the same analysis: from ∥x∥∞≤∥x∥p≤n1/p∥x∥∞\|\boldsymbol{x}\|_\infty\le\|\boldsymbol{x}\|_p\le n^{1/p}\|\boldsymbol{x}\|_\infty, all pp-norms on Rn\mathbb{R}^n are equivalent, and the pp-metrics are strongly equivalent, with the same convergent sequences.

A common slip is to drop the outer root and use ∑i∣xi∣p\displaystyle \sum_i|x_i|^p as the norm. For p>1p>1 this is not a norm: it scales like ∣c∣p|c|^p instead of ∣c∣|c|, so absolute homogeneity fails.


Key Results

  • The smallest permissible value for pp in the pp-norm is 11.

Examples

  • The Euclidean distance d2d_2 is a particular pp-metric when p=2p=2.
  • The taxicab distance d1d_1 is a particular pp-metric when p=1p=1.
  • The maximum norm ∥⋅∥∞\|\cdot\|_\infty is a particular pp-norm when p=+∞p=+\infty.

Prerequisites

Sources

Aliases: p norm, p metric, Minkowski distance Symbols: element of, infinity, real numbers, sum

Last updated: 22 October 2026 19:04