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Fundamental Bridge

Proposition

For any event AA, let 𝟙1A\indicator_A equal one on AA and zero outside AA. The fundamental bridge is

E[𝟙1A]=P(A).\mathbb{E}[\indicator_A]=\mathbb{P}(A).

The expectation always exists because the indicator is bounded.


Interpretation

The fundamental bridge says that the probability of an event equals the expected value of its indicator. It lets every probability be written as an expectation, and every expected count as a sum of probabilities.

Two probability bars of an indicator variable, 1 - P(A) at the value 0 and P(A) at the value 1, balanced at the point P(A).

In the figure P(A)=0.3\mathbb{P}(A)=0.3: the indicator equals 00 with probability 0.70.7, when AA did not occur, and 11 with probability 0.30.3, when it did. Treating the two bars as weights, their balance point, the expectation, lies at 0⋅0.7+1⋅0.3=0.3=P(A)0\cdot0.7+1\cdot0.3=0.3=\mathbb{P}(A).

The proof is one line, since 𝟙1A\indicator_A is a Bernoulli variable with parameter P(A)\mathbb{P}(A). The identity becomes useful together with linearity of expectation: if X=𝟙1A1+⋯+𝟙1AnX=\indicator_{A_1}+\cdots+\indicator_{A_n} counts how many of the events occur, then E[X]=P(A1)+⋯+P(An)\mathbb{E}[X]=\mathbb{P}(A_1)+\cdots+\mathbb{P}(A_n), whether or not the events are independent. For nn tosses with heads probability pp this gives the binomial mean npnp. If nn letters are put into nn envelopes at random, letter ii lands in its own envelope with probability 1/n1/n, so the expected number of correctly placed letters is n⋅1n=1n\cdot\tfrac{1}{n}=1 for every nn, although these events are dependent.

The bridge does not say that 𝟙1A\indicator_A equals P(A)\mathbb{P}(A). The indicator only takes the values 00 and 11; P(A)\mathbb{P}(A) is its average value, and it is usually not a value the indicator takes.


Key Results

  • E[𝟙1A]=1P(A)+0P(Ac)=P(A)\mathbb{E}[\indicator_A]=1\mathbb{P}(A)+0\mathbb{P}(A^c)=\mathbb{P}(A).
  • E[∑i𝟙1Ai]=∑iP(Ai)\displaystyle \mathbb{E}[\sum_i\indicator_{A_i}]=\sum_i\mathbb{P}(A_i) for finitely many events, without independence.

Examples

  • For an even result on a fair die, E[𝟙1A]=1/2\mathbb{E}[\indicator_A]=1/2.
  • For 1010 components each failing with probability 0.020.02, the expected failure count is 0.20.2, even if failures are dependent.

Prerequisites

Sources

Aliases: indicator bridge, expectation of an indicator Keywords: probability-expectation bridge Symbols: sum

Last updated: 20 October 2026 03:02