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Disjoint Events

Definition

Let AA and BB be events. The events AA and BB are disjoint or mutually exclusive if

A∩B=∅.A\cap B=\varnothing.

Interpretation

Disjoint events have no outcome in common, so they cannot happen on the same run of the experiment: once one of them occurs, the other is ruled out.

A rectangle for the sample space with two separate discs A and B that do not overlap.

The two discs do not overlap, so their intersection is the empty set, and by the third axiom of probability their probabilities add: for a fair die, A={1,2}A=\{1,2\} and B={6}B=\{6\} are disjoint and P(A∪B)=26+16=12\mathbb{P}(A\cup B)=\tfrac{2}{6}+\tfrac{1}{6}=\tfrac{1}{2}.

Disjointness is a property of the events as sets, not of their probabilities. For more than two events it means pairwise disjoint: {1,2}\{1,2\}, {2,3}\{2,3\} and {1,3}\{1,3\} have no outcome common to all three, yet no two of them are disjoint.

A common slip is to read "disjoint" as "unrelated": knowing that AA occurred tells you that BB did not. This differs from independence, where knowing that one event occurred does not change the probability of the other.


Key Results

  • Disjoint events have empty intersection.
  • For disjoint events, P(A∪B)=P(A)+P(B)\mathbb{P}(A\cup B)=\mathbb{P}(A)+\mathbb{P}(B).
  • Disjoint events AA and BB are independent only if P(A)=0\mathbb{P}(A)=0 or P(B)=0\mathbb{P}(B)=0, because P(A∩B)=0\mathbb{P}(A\cap B)=0 must then equal P(A)P(B)\mathbb{P}(A)\mathbb{P}(B).

Examples

  • On one die roll, rolling a one and rolling a six are disjoint events.
  • Drawing a red card and drawing a black card on a single draw are disjoint.
  • Passing and failing the same exam attempt are mutually exclusive events.

Prerequisites

Sources

Aliases: mutually exclusive events, incompatible events, pairwise disjoint events Symbols: intersection, union

Last updated: 27 October 2026 11:52