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Force of Mortality


Definition

Under the course's absolutely continuous survival model, the force of mortality at attained age x+tx+t (the age reached tt years after age xx) is

μx+t=fx(t)Sx(t)=−ddtlog⁡Sx(t),\mu_{x+t}=\frac{f_x(t)}{S_x(t)}=-\frac{\mathrm{d}}{\mathrm{d}t}\log S_x(t),

where Sx(t)>0S_x(t)>0 and the derivative exists. Equivalently, it is the limit of P(t<Tx≤t+h∣Tx>t)/h\mathbb{P}(t<T_x\le t+h\mid T_x>t)/h as h↓0h\downarrow0.


Interpretation

Mortality is measured per unit of time among those still alive. The force can exceed one; it is a rate and must be multiplied by a short duration to approximate a probability.

Survivor function exp(-0.02t) with its tangent at time 20 reaching zero at time 70, so the reciprocal of the force of mortality, 50 years, is marked along the time axis.

The figure uses the Examples force 0.020.02, so Sx(t)=e−0.02tS_x(t)=\mathrm{e}^{-0.02t}. At t=20t=20 the tangent to SxS_x has slope −fx(20)-f_x(20). Dividing the height Sx(20)S_x(20) by this rate of decline gives the time the tangent needs to reach zero, Sx(20)/fx(20)=1/μx+20=50S_x(20)/f_x(20)=1/\mu_{x+20}=50 years, so a high force means a tangent that is steep relative to the height of the curve. Because this force is constant, the tangent at any tt reaches zero 50 years later.

Here TxT_x is future lifetime, Sx(t)S_x(t) is its survivor function, and fx(t)f_x(t) is its probability density function. Dividing the density by the probability of still being alive expresses a death rate among survivors rather than among all lives originally insured.


Key Results

  • tpx=exp⁡(−∫0tμx+s ds){}_tp_x=\exp(-\int_0^t\mu_{x+s}\,\mathrm{d}s) and fx(t)=tpxμx+tf_x(t)={}_tp_x\mu_{x+t}.
  • A constant force λ>0\lambda>0 gives tpx=e−λt{}_tp_x=\mathrm{e}^{-\lambda t}, an exponential future lifetime.
  • An increasing force means that the death rate among survivors rises with time survived (positive duration dependence); a decreasing force means that it falls (negative duration dependence).
  • For a finite force at xx, hqx=μxh+o(h){}_hq_x=\mu_xh+o(h), with little-oo notation.

Examples

At constant force 0.020.02 per year, the one-year death probability is 1−e−0.02≈0.019801-\mathrm{e}^{-0.02}\approx0.01980, rather than exactly 0.020.02.


Prerequisites



Sources

Aliases: hazard rate, instantaneous mortality rate, hazard function, mortality intensity, intensity of mortality Keywords: mu x+t = f(t)/S(t), t p x = exp(-integral of mu), duration dependence, constant force gives an exponential lifetime, death rate among survivors Symbols: integral, lambda, mu

Last updated: 17 October 2026 21:53